(2(x/(x+4))^2)-(5(x/(x+4)))-3=0

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Solution for (2(x/(x+4))^2)-(5(x/(x+4)))-3=0 equation:


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

2*(x/(x+4))^2-(5*(x/(x+4)))-3 = 0

2*(x/(x+4))^2-5*x*(x+4)^-1-3 = 0

(2*x^2)/((x+4)^2)+(-5*x)/(x+4)-3 = 0

(2*x^2)/((x+4)^2)+(-5*x*(x+4))/((x+4)^2)+(-3*(x+4)^2)/((x+4)^2) = 0

2*x^2-5*x*(x+4)-3*(x+4)^2 = 0

-3*x^2-3*x^2-20*x-24*x-48 = 0

-6*x^2-44*x-48 = 0

-6*x^2-44*x-48 = 0

-2*(3*x^2+22*x+24) = 0

3*x^2+22*x+24 = 0

DELTA = 22^2-(3*4*24)

DELTA = 196

DELTA > 0

x = (196^(1/2)-22)/(2*3) or x = (-196^(1/2)-22)/(2*3)

x = -4/3 or x = -6

-2*(x+6)*(x+4/3) = 0

(-2*(x+6)*(x+4/3))/((x+4)^2) = 0

(-2*(x+6)*(x+4/3))/((x+4)^2) = 0 // * (x+4)^2

-2*(x+6)*(x+4/3) = 0

( x+4/3 )

x+4/3 = 0 // - 4/3

x = -4/3

( x+6 )

x+6 = 0 // - 6

x = -6

x in { -4/3, -6 }

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